




For a uniformly charged thin spherical shell of radius \( R \) and total charge \( Q \), the electric potential inside the shell (\( r < R \)) is constant and equal to the potential at the surface:
\( V = \frac{kQ}{R} \)
where \( k \) is Coulomb's constant. This means the potential does *not* change as you move from the center towards the surface.
For points outside the shell (\( r > R \)), the electric potential is the same as that of a point charge located at the center of the shell:
\( V = \frac{kQ}{r} \)
The potential decreases as the distance \( r \) increases, following an inverse relationship.
Based on the above analysis:
This corresponds to a graph that is constant for \( r < R \) and then decreases hyperbolically for \( r > R \).
The correct graphical representation is Option (4).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)