Question

For a thin prism, if the angle of the prism is \( A \) with a refractive index of 1.6, then the angle of minimum deviation will be …….

Hint:

For a thin prism, the angle of minimum deviation is given by \( \delta_m = (n - 1) A \). The deviation increases with the refractive index \( n \) and prism angle \( A \).

Answer 1

Step 1: Understanding the Minimum Deviation Formula 
For a thin prism, the formula for the angle of minimum deviation (\( \delta_m \)) is: \[ \delta_m = (n - 1) A \] where:
- \( n \) is the refractive index of the prism,
- \( A \) is the angle of the prism,
- \( \delta_m \) is the minimum deviation. 
Step 2: Substituting the Given Values 
Given: - \( n = 1.6 \), - \( A = 4^\circ \). 
Step 3: Calculating Minimum Deviation 
\[ \delta_m = (1.6 - 1) \times 4^\circ \] \[ \delta_m = 0.6 \times 4^\circ \] \[ \delta_m = 2.4^\circ \] Thus, the angle of minimum deviation is \( 2.4^\circ \).