Step 1: Use stoichiometric rate relation.
For the reaction:
2A + B → C + D
Rate = −(1/2) d[A]/dt = d[C]/dt.
Step 2: Substitute given rate of consumption of A.
Given: −d[A]/dt = 0.1 mol L$^{-1}$ s$^{-1}$.
Step 3: Apply stoichiometric coefficient.
d[C]/dt = (1/2)(0.1)
= 0.05 mol L$^{-1}$ s$^{-1}$.
Step 4: Conclusion.
Thus, the rate of formation of C is 0.05 mol L$^{-1}$ s$^{-1}$.