
At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)
A small spherical ball having charge \( q \) and mass \( m \), is tied to a thin massless non-conducting string of length \( l \). The other end of the string is fixed to an infinitely extended thin non-conducting sheet with uniform surface charge density \( \sigma \). Under equilibrium, the string makes an angle of 45° with the sheet as shown in the figure. Then \( \sigma \) is given by \[ g \text{ is the acceleration due to gravity and } \epsilon_0 \text{ is the permittivity of free space.} \] 
