The work done in moving a charge \( q \) from \( (0, 0, b) \) to \( (0, 0, b) \) is \( \frac{qp}{4\pi \epsilon_0 b^2} \).
The electrostatic potential at \( (b, 0, 0) \) is zero.
If a charge \( q \) is kept at \( (0, 0, b) \), it will exert a force of magnitude \( \frac{qp}{4\pi \epsilon_0 b^3} \) on the dipole.
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The Correct Option isD
Solution and Explanation
Step 1: Understanding the dipole electric field.
The electric field of a dipole varies with distance and direction. The force on a charge placed near a dipole is determined by the dipole field and the interaction between the dipole moment and the charge. The force on the charge is given by \( \frac{qp}{4\pi \epsilon_0 b^3} \). Step 2: Conclusion.
Thus, the correct answer is option (D).