Question:
For a particle executing simple harmonic motion, match the following statements (conditions) from column I to statements (shapes of graph) in column II.
For a particle executing simple harmonic motion, match the following statements (conditions) from column I to statements (shapes of graph) in column II.
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For SHM, remember:
- Velocity vs. displacement: Circle
- Acceleration vs. displacement: Straight line
- Acceleration vs. time: Sinusoidal
- Acceleration vs. velocity (if \(\omega \neq 1\)): Ellipse
- Velocity vs. displacement: Circle
- Acceleration vs. displacement: Straight line
- Acceleration vs. time: Sinusoidal
- Acceleration vs. velocity (if \(\omega \neq 1\)): Ellipse
Updated On: Jan 2, 2026
a-iv, b- i, c-ii, d-iii
a-iii, b-i, c-ii, d-iv
a-iii, b-ii, c-i, d-iv
a-iv, b-ii, c-i, d-iii
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The Correct Option is B
Solution and Explanation
- The velocity-displacement graph of SHM forms a circle (\( a-iii \)).
- The acceleration-displacement graph is a straight line, as acceleration is directly proportional to displacement (\( b-i \)).
- The acceleration-time graph follows a sinusoidal shape since acceleration varies periodically (\( c-ii \)).
- The acceleration-velocity graph forms an ellipse when \( \omega \neq 1 \) (\( d-iv \)).
- The acceleration-displacement graph is a straight line, as acceleration is directly proportional to displacement (\( b-i \)).
- The acceleration-time graph follows a sinusoidal shape since acceleration varies periodically (\( c-ii \)).
- The acceleration-velocity graph forms an ellipse when \( \omega \neq 1 \) (\( d-iv \)).
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