For a metal ion, the calculated magnetic moment is 4.90 BM. This metal ion has ______ number of unpaired electrons.
Correct Answer: 4
Approach Solution - 1
The magnetic moment of a complex is 4.9 B.M. Thus, unpaired electrons maybe 4. The expression for the magnetic moment is μ= \(\sqrt{n(n+2)}\)
Substitute values in the above expression.
4.9= \(\sqrt{n(n+2)}\)
24.01=n(n+2)
⇒ n=4.
So, the correct answer is 4.
Approach Solution -2
Step 1: Using the formula for the magnetic moment.
The magnetic moment (\( \mu \)) is related to the number of unpaired electrons (n) by the formula: \[ \mu = \sqrt{n(n+2)} \] where \( \mu \) is the magnetic moment in Bohr Magneton (BM) and \( n \) is the number of unpaired electrons.
Step 2: Substituting the given value of magnetic moment.
We are given that \( \mu = 4.90 \, \text{BM} \). Substituting this value into the formula: \[ 4.90 = \sqrt{n(n+2)} \]
Step 3: Solving for \( n \).
Squaring both sides: \[ (4.90)^2 = n(n + 2) \] \[ 24.01 = n(n + 2) \] Expanding the equation: \[ 24.01 = n^2 + 2n \] Rearranging the equation: \[ n^2 + 2n - 24.01 = 0 \] Solving this quadratic equation for \( n \) gives: \[ n = 4 \] Thus, the metal ion has 4 unpaired electrons.
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main d -and f -Block Elements Questions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- Number of metal ions characterized by flame test among the following is _______.
$\text{Sr}^{2+}, \text{Ba}^{2+}, \text{Ca}^{2+}, \text{Cu}^{2+}, \text{Zn}^{2+}, \text{Co}^{2+}, \text{Fe}^{2+}$ - Match the following :
(a) \([Cr(H_2O)_6]^{+3}\) (i) \(t^2_{2g}eg^0\) (b) \([Fe(H_2O)_6]^{+3}\) (ii) \(t^3_{2g}eg^0\) \((c) [Ni(H_2O)_6]^{+2}\) (iii) \(t^3_{2g}eg^2\) (d) \([V(H_2O)_6]^{+3}\) (iv) \(t^6_{2g}eg^2\) - The compound that is white in color is
- The 'Spin only' Magnetic moment for \([Ni(NH_3)_6]^{2+}\) is _____ × \(10^{−1}\) BM. (given = Atomic number of Ni : 28)
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
Concepts Used:
D and F Block Elements
The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements.
They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.
Read More: The d and f block elements