The critical angle (\(C\)) for total internal reflection is given by the relation:
\[ \sin C = \frac{1}{\mu} \]
where \( \mu \) is the refractive index of the denser medium relative to the rarer medium.
Important: Refractive index (\(\mu\)) varies with wavelength (colour) due to dispersion. For visible light, the refractive index is highest for violet (shortest wavelength) and lowest for red (longest wavelength).
Step-by-Step Logic:
\[ \sin C = \frac{1}{\mu} \]
Therefore, among visible colours, red will have the smallest refractive index, and thus the maximum critical angle.
The critical angle \( \theta_c \) for a pair of transparent media is given by the equation: \[ \sin \theta_c = \frac{n_2}{n_1} \] where:
\( n_1 \) is the refractive index of the denser medium,
\( n_2 \) is the refractive index of the rarer medium.
The critical angle depends on the refractive index of the medium. The refractive index decreases as the wavelength of light increases. Since red light has the longest wavelength and thus the smallest refractive index among the visible spectrum, the critical angle is the largest for red light.
Therefore, the critical angle for red light is maximum.
\(XPQY\) is a vertical smooth long loop having a total resistance \(R\), where \(PX\) is parallel to \(QY\) and the separation between them is \(l\). A constant magnetic field \(B\) perpendicular to the plane of the loop exists in the entire space. A rod \(CD\) of length \(L\,(L>l)\) and mass \(m\) is made to slide down from rest under gravity as shown. The terminal speed acquired by the rod is _______ m/s. 
A biconvex lens is formed by using two plano-convex lenses as shown in the figure. The refractive index and radius of curvature of surfaces are also mentioned. When an object is placed on the left side of the lens at a distance of \(30\,\text{cm}\), the magnification of the image will be: 
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2