0.4606
0.9212
For a first-order reaction, the rate constant \( k \) can be calculated using the formula for first-order kinetics: \[ k = \frac{1}{t} \ln\left(\frac{[A]_0}{[A]}\right) \] where \([A]_0\) is the initial concentration, \([A]\) is the concentration at time \( t \), and \( \ln \) denotes the natural logarithm. Given: \([A]_0 = 0.1 \, \text{M}\), \([A] = 0.001 \, \text{M}\), and \( t = 5 \, \text{min} \).
Apply the values to the formula: \[ k = \frac{1}{5} \ln\left(\frac{0.1}{0.001}\right) \]
Simplify the fraction in logarithm: \[ \frac{0.1}{0.001} = 100 \] Hence, \[ k = \frac{1}{5} \ln(100) \]
Calculate the natural logarithm: \[ \ln(100) \approx 4.6052 \]
Substitute back: \[ k = \frac{1}{5} \times 4.6052 = 0.9210 \, \text{min}^{-1} \]
The rate constant \( k \) for this reaction is approximately \(0.9212 \, \text{min}^{-1}\).
(i) Write any two differences between order and molecularity.
(ii) What do you mean by pseudo order reaction?
Given below are two statements:
Statement I: Transfer RNAs and ribosomal RNA do not interact with mRNA.
Statement II: RNA interference (RNAi) takes place in all eukaryotic organisms as a method of cellular defence.
In the light of the above statements, choose the most appropriate answer from the options given below:
Chemical kinetics is the description of the rate of a chemical reaction. This is the rate at which the reactants are transformed into products. This may take place by abiotic or by biological systems, such as microbial metabolism.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time. To be more specific, it can be expressed in terms of: (i) the rate of decrease in the concentration of any one of the reactants, or (ii) the rate of increase in concentration of any one of the products. Consider a hypothetical reaction, assuming that the volume of the system remains constant. R → P
Read More: Chemical Kinetics MCQ