Question

What is the code for the string NABAQE? Coding Table: \[ \begin{array}{|c|c|} \hline \text{Letter} & \text{Code} \hline R& 4 E& 9 A& 3 U&\delta M& 6 D&\% F& 5 P& 8 Q& 1 I& 2 O& @ H&* N& 7 W&\# Z&\copyright B& 6 \hline \end{array} \]

• A. 263$4\#$
• B. 326$4\#$
• C. 362$4\#$
• D. $2$64$\#3$
• A. 5d#7$
• B. 5dd#7$
• C. D17#7$
• D. 511#7$
• A. \(\copyright6289\)
• B. \(\copyright2689\%\)
• C. \(@6289\copyright\)
• D. \(\copyright6209\%\)
• A. \(\#\%978*\)
• B. \(\#\%9\#8*7\)
• C. \(\%9\#8*\)
• D. \(\#9\%78*\)
• A. \(@7\#80\%\)
• B. \(\#7\#80\%\)
• C. \(@78\#\copyright\%\)
• D. \(\%@7\#@\%\)

Answer 1

The Correct Option is B

Step 1: Write the string. \[ N\ A\ B\ A\ Q\ E \]

Step 2: Check conditions. First letter = N (consonant) Third letter = B (consonant) No special interchange condition applies.

Step 3: Convert each letter into code. \[ N \rightarrow 2 \] \[ A \rightarrow 3 \] \[ B \rightarrow 6 \] \[ A \rightarrow 2 \] \[ Q \rightarrow 4 \] \[ E \rightarrow \# \] Thus the code obtained is \[ 3264\# \] Hence the correct answer is \[ \boxed{3264\#}. \]

Answer 2

Step 1: Observe the string. \[ F\ W\ Z\ E\ R\ A \]

Step 2: Check the conditions. First letter is a consonant (\(F\)). Third letter is also a consonant (\(Z\)). According to the coding rule, the second and third letters are coded using the code of the third letter.

Step 3: Apply the coding table. \[ F \rightarrow 5 \] \[ W,Z \rightarrow 1,1 \] \[ E \rightarrow \# \] \[ R \rightarrow 7 \] \[ A \rightarrow \$ \] Therefore the code becomes \[ 511\#7\$ \] Hence the answer is \[ \boxed{511\#7\$}. \]

Answer 3

Concept: In coding-decoding questions, we must first convert every letter using the coding table and then carefully verify whether any special condition modifies the obtained code.

Step 1: Write the given string. \[ H\ U\ B\ D\ I\ N \]

Step 2: Check the special conditions. First letter = \(H\) (consonant) Third letter = \(B\) (consonant) The condition requiring interchange of first and third symbols does not apply because the third letter is not a vowel. The condition involving first letter vowel also does not apply. Hence direct coding is used.

Step 3: Replace each letter by its code. \[ H \rightarrow \copyright \] \[ U \rightarrow 2 \] \[ B \rightarrow 6 \] \[ D \rightarrow 8 \] \[ I \rightarrow 9 \] \[ N \rightarrow \% \]

Step 4: Write the complete code. \[ \copyright2689\% \] Therefore the required code is \[ \boxed{\copyright2689\%} \]

Answer 4

Step 1: Write the word. \[ E\ M\ I\ R\ D\ P \]

Step 2: Check the special condition. The first letter \(E\) is a vowel and the fourth letter \(R\) is a consonant. According to the given rule: If the first letter is a vowel and the fourth letter is a consonant, both are coded using the code of that vowel. Code of \(E\) is \[ \# \] Hence both first and fourth positions become \(\#\).

Step 3: Code the remaining letters. \[ M \rightarrow \% \] \[ I \rightarrow 9 \] \[ D \rightarrow 7 \] \[ P \rightarrow 8 \] \[ R \rightarrow * \]

Step 4: Form the final code. \[ \#\%978* \] Therefore the answer is \[ \boxed{\#\%978*} \]

Answer 5

Step 1: Write the given string. \[ O\ R\ E\ D\ H\ M \]

Step 2: Apply the special condition. The first letter \(O\) is a vowel. The fourth letter \(D\) is a consonant. Hence the rule states that both first and fourth letters must be coded using the code of the first vowel. Code of \(O\) is \[ \# \] Therefore: \[ O \rightarrow \# \] and \[ D \rightarrow \# \]

Step 3: Encode the remaining letters. \[ R \rightarrow 7 \] \[ E \rightarrow \# \] \[ H \rightarrow 8 \] \[ M \rightarrow 0 \] \[ \text{Remaining symbol } = \% \]

Step 4: Write the final code. \[ \#7\#80\% \] Thus the correct code is \[ \boxed{\#7\#80\%} \]