{"@context":"https://schema.org/","@type":"Quiz","dateCreated":"2024-04-26T11:39:48.852Z","dateModified":"2024-04-26T11:39:48.852Z","typicalAgeRange":"11-18","educationalLevel":"CUET (UG)","assesses":"Chemistry - Gibbs Free Energy","educationalAlignment":[{"@type":"AlignmentObject","alignmentType":"educationalTopic","targetName":"Gibbs Free Energy"},{"@type":"AlignmentObject","alignmentType":"educationalSubject","targetName":"Chemistry"},{"@type":"AlignmentObject","alignmentType":"educationalExam","targetName":"CUET (UG)"}],"name":"Quiz about Gibbs Free Energy","about":{"@type":"Thing","name":"Chemistry - Gibbs Free Energy"},"hasPart":[{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"intermediate","name":"Question About Gibbs Free Energy","text":"Following reaction takes place in Daniell cell: $$Zn(s)+Cu^{2+} (aq) \\rightarrow Zn^{2+} (aq) + Cu(s); E^0_{cell} = 1.1V$$ Standard Gibbs energy, in this case will be}","encodingFormat":"text/markdown","comment":{"@type":"Comment","text":"\"\""},"suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

-2123.0 KJ/mol

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

-212.3 KJ/mol

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

+212.3 KJ/mol

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":3,"encodingFormat":"text/markdown","text":"

+21227 KJ/mol

","comment":{"@type":"Comment","text":"\"\""}}],"acceptedAnswer":{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

-212.3 KJ/mol

","comment":{"@type":"Comment","text":"\"\""},"answerExplanation":{"@type":"comment","text":"The correct option is (B): -212.3 KJ/mol"}}}]}

Following reaction takes place in Daniell cell:\(Zn(s)+Cu^{2+} (aq) \rightarrow Zn^{2+} (aq) + Cu(s); E^0_{cell} = 1.1V\)Standard Gibbs energy, in this case will be

The Correct Option is B

Solution and Explanation

Top Questions on Gibbs Free Energy

Questions Asked in CUET exam

Following reaction takes place in Daniell cell:
\(Zn(s)+Cu^{2+} (aq) \rightarrow Zn^{2+} (aq) + Cu(s); E^0_{cell} = 1.1V\)
Standard Gibbs energy, in this case will be