Question:
Five years ago, A was three times as old as B. Now, A is twice as old as B. What is A's current age?
Five years ago, A was three times as old as B. Now, A is twice as old as B. What is A's current age?
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Set variables for "Current Age" to avoid confusion with "X years ago".
Updated On: Jun 12, 2026
- 20
- 15
- 25
- 30
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Linear equations in one variable representing current ages.
Step 2: Detailed Explanation:
1. Let present age of B be \( x \), then A is \( 2x \).
2. 5 years ago: \( A-5 = 3(B-5) \).
3. \( 2x - 5 = 3(x - 5) = 3x - 15 \).
4. \( x = 10 \). Age of A = \( 2 \times 10 = 20 \).
Step 3: Final Answer:
A's current age is 20.
Linear equations in one variable representing current ages.
Step 2: Detailed Explanation:
1. Let present age of B be \( x \), then A is \( 2x \).
2. 5 years ago: \( A-5 = 3(B-5) \).
3. \( 2x - 5 = 3(x - 5) = 3x - 15 \).
4. \( x = 10 \). Age of A = \( 2 \times 10 = 20 \).
Step 3: Final Answer:
A's current age is 20.
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