Question:
Five years ago, A's age was three times B's age. At present, A's age is twice B's age. What is A's present age?
Five years ago, A's age was three times B's age. At present, A's age is twice B's age. What is A's present age?
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Translate every age statement into an algebraic equation before solving. Age problems become simple linear equations.
Updated On: Jun 11, 2026
- 20 years
- 25 years
- 30 years
- 35 years
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The Correct Option is C
Solution and Explanation
Concept:
Age problems are solved by converting verbal statements into algebraic equations.
Let present ages be represented by variables.
Step 1: Assume present ages. Let present age of B be \[ x \] Then present age of A is \[ 2x \] because A is currently twice B's age.
Step 2: Use the condition five years ago. Five years ago: \[ A=2x-5 \] \[ B=x-5 \] Given: \[ 2x-5=3(x-5) \]
Step 3: Solve the equation. \[ 2x-5=3x-15 \] \[ 10=x \] Hence, \[ B=10 \] and \[ A=20 \] Thus, \[ \boxed{\text{Answer = (C)}} \]
Step 1: Assume present ages. Let present age of B be \[ x \] Then present age of A is \[ 2x \] because A is currently twice B's age.
Step 2: Use the condition five years ago. Five years ago: \[ A=2x-5 \] \[ B=x-5 \] Given: \[ 2x-5=3(x-5) \]
Step 3: Solve the equation. \[ 2x-5=3x-15 \] \[ 10=x \] Hence, \[ B=10 \] and \[ A=20 \] Thus, \[ \boxed{\text{Answer = (C)}} \]
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