Question

Five groups of letters are given. One of these groups is different from the other four. Find the odd one. YDEUZ, ASHBR, OZPEQ, AXCMF, HLXEF

• A. YDEUZ
• B. ASHBR
• C. OZPEQ
• D. AXCMF

Hint:

In odd-one-out letter-group questions, convert letters into their alphabetical positions and look for common patterns such as consecutive letters, equal gaps, symmetry, or reverse-order relationships. The group that breaks the common pattern is the answer.

Answer 1

The Correct Option is D

Concept:

In classification problems, we compare internal relationships among letters in each group. A common method is to convert letters into their alphabetical positions:

\[ A=1,\; B=2,\; \dots,\; Z=26 \]

Then we check for patterns such as consecutive letters, arithmetic relations, or sequences.

Step 1: Convert letters into positions \[ \begin{aligned} \text{YDEUZ} & : 25,\;4,\;5,\;21,\;26 \\ \text{ASHBR} & : 1,\;19,\;8,\;2,\;18 \\ \text{OZPEQ} & : 15,\;26,\;16,\;5,\;17 \\ \text{AXCMF} & : 1,\;24,\;3,\;13,\;6 \\ \text{HLXEF} & : 8,\;12,\;24,\;5,\;6 \end{aligned} \] 
Step 2: Check for consecutive alphabet pairs

• YDEUZ: D–E (4–5) and Y–Z (25–26) are consecutive.
• ASHBR: A–B (1–2) and S–R (19–18) form consecutive pairs.
• OZPEQ: P–Q (16–17) are consecutive letters.
• HLXEF: E–F (5–6) are consecutive.
• AXCMF: No consecutive letter pairs exist.

Step 3: Identify the odd group

All groups except AXCMF contain at least one pair of consecutive letters. Therefore, AXCMF is the odd one out.

\[ \boxed{\text{AXCMF}} \]

Final Answer: Option (D)