Question:

Find the velocity of an electron in the fourth Bohr orbit of hydrogen atom.

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In hydrogen atom, \[ v_n=\frac{2.18\times10^6}{n}\;m/s \] Velocity decreases inversely with principal quantum number.
  • \(2.18\times10^6\,m/s\)
  • \(5.45\times10^5\,m/s\)
  • \(1.09\times10^6\,m/s\)
  • \(4.00\times10^5\,m/s\)
Show Solution
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The Correct Option is B

Solution and Explanation

Concept: According to Bohr's model, \[ v_n=\frac{v_1}{n} \] where \[ v_1=2.18\times10^6\,m/s \] for hydrogen atom.

Step 1: Use \(n=4\).
\[ v_4=\frac{2.18\times10^6}{4} \] \[ v_4=5.45\times10^5\,m/s \] Final Answer: \[ \boxed{5.45\times10^5\,m/s} \] Hence the correct option is \[ \boxed{(B)} \]
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