
90°
60°
30°
45°
To find the angle of emergence from the prism, we use the principles of refraction and the prism formula. The relevant formula is the prism formula, which relates the angle of incidence \(i\), the angle of emergence \(e\), the angle of the prism \(A\), and the refractive index \(\mu\) of the material.
The formula for refraction at two surfaces is:
\(\mu = \frac{\sin(\frac{A + \delta}{2})}{\sin(\frac{A}{2})}\)
Given:
Since the refractive index is given as \(\sqrt{3}\), the minimum deviation \( \delta \) needs to be found when light passes symmetrically through the prism:
\(\sqrt{3} = \frac{\sin(\frac{60 + \delta}{2})}{\sin(30)}\)
Since \(\sin(30^\circ) = \frac{1}{2}\), the equation becomes:
\(\sqrt{3} = 2 \sin(\frac{60 + \delta}{2})\)
Simplifying gives:
\(\sin(\frac{60 + \delta}{2}) = \frac{\sqrt{3}}{2}\)
Thus, \(\frac{60 + \delta}{2} = 60^\circ\)
Solving for \(\delta\), we get:
\(\delta = 60^\circ\)
In symmetric passage, angle of incidence \(i\) is equal to angle of emergence \(e\), so:
\(e = \frac{(A + \delta) - A}{2}\)
Thus:
\(e = \frac{(60 + 60) - 60}{2} = 60^\circ\)
Therefore, the angle of emergence from the prism is 60°.
\(XPQY\) is a vertical smooth long loop having a total resistance \(R\), where \(PX\) is parallel to \(QY\) and the separation between them is \(l\). A constant magnetic field \(B\) perpendicular to the plane of the loop exists in the entire space. A rod \(CD\) of length \(L\,(L>l)\) and mass \(m\) is made to slide down from rest under gravity as shown. The terminal speed acquired by the rod is _______ m/s. 
A biconvex lens is formed by using two plano-convex lenses as shown in the figure. The refractive index and radius of curvature of surfaces are also mentioned. When an object is placed on the left side of the lens at a distance of \(30\,\text{cm}\), the magnification of the image will be: 
Given below are two statements:
Statement I: Transfer RNAs and ribosomal RNA do not interact with mRNA.
Statement II: RNA interference (RNAi) takes place in all eukaryotic organisms as a method of cellular defence.
In the light of the above statements, choose the most appropriate answer from the options given below:
Refraction is the bending of a wave when it enters a medium where its speed is different. The refraction of light when it passes from a fast medium to a slow medium bends the light ray toward the normal boundary between the two media. The amount of bending depends on the indices of refraction of the two media and is described quantitatively by Snell's Law.
If you ever observe a pencil dipped into water, you’ll notice that it seems to be tilted at an angle at the interface of air and water, or the bottom of a tub or a tank that contains water seems to be raised. This phenomenon is caused due to the process of refraction of light. Refraction of light is the bending of the light wave, passing from one medium to another, which is caused due to the difference in the density of the two mediums.
The main cause of refraction is the variation in the velocity of the light when it enters different mediums. The speed of light in the air is faster than that of water. So, the speed of the light increases when it travels from water to air, and similarly, the speed decreases when it travels from air to water.
In the below figure, it is shown why the printed alphabets appear to have risen when seen through a glass slab. This is because when the light travels from air to glass, the speed gets reduced and the light moves toward the normal, that is the light rays move towards the NN’ normal from its original path. Likewise, when the light ray travels from glass to air, its speed gets increased and it moves away from the normal.
There are two Laws of Refraction. They are: