Question

Find the value of:
(i) -4÷\(\frac{2}{3}\)
(ii) -\(\frac{3}{5}\)÷2
(iii) -\(\frac{4}{5}\)÷(-3)
(iv) -\(\frac{1}{8}\)÷\(\frac{3}{4}\)
(v) -\(\frac{2}{13}\)÷\(\frac{1}{7}\)
(vi) -\(\frac{7}{12}\)÷(-\(\frac{2}{13}\))
(vii) \(\frac{3}{13}\)÷(-\(\frac{4}{65}\))

Answer 1

(i)-4÷\(\frac{2}{3}\)
= -4×\(\frac{3}{2}\)
= -\(\frac{12}{2}\)
= -6

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(ii) -\(\frac{3}{5}\)÷2
= -\(\frac{3}{5}\)×\(\frac{1}{2}\)
= -\(\frac{3}{10}\)

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(iii) -\(\frac{4}{5}\)÷(-3)
= -\(\frac{4}{5}\)×\(\frac{1}{-3}\)
= (-4)×\(\frac{1}{5}\)×(-3)
= \(\frac{-4}{-15}\)
= \(\frac{4}{15}\)

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(iv) -\(\frac{1}{8}\)÷\(\frac{3}{4}\)
= -\(\frac{1}{8}\)×\(\frac{4}{3}\)
= -\(\frac{4}{24}\)
= -\(\frac{1}{6}\)

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(v) -\(\frac{2}{13}\)÷\(\frac{1}{7}\)
= -\(\frac{2}{13}\)×7
= -\(\frac{14}{13}\)

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(vi) -\(\frac{7}{12}\)÷(-\(\frac{2}{13}\))
= -\(\frac{7}{12}\)×\(\frac{13}{-2}\)
= (-7)×\(\frac{13}{12}\)×(-2)
=\(\frac{91}{24}\)

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(vii) \(\frac{3}{13}\)÷(-\(\frac{4}{65}\))
= \(\frac{3}{13}\)×\(\frac{65}{-4}\)
= 3×\(\frac{65}{13}\)×(-4)
= \(\frac{195}{-52}\)
= -\(\frac{15}{4}\)