Question

Find the product:
(i)\(\frac{9}{2}\)×(-\(\frac{7}{4}\))
(ii) \(\frac{3}{10}\)×(-9)
(iii) -\(\frac{6}{5}\)×\(\frac{9}{11}\)
(iv) \(\frac{3}{7}\)×(-\(\frac{2}{5}\))
(v) \(\frac{3}{11}\)×\(\frac{2}{5}\)
(vi) \(\frac{3}{-5}\) ×\(\frac{-5}{3}\)

Answer 1

(i) \(\frac{9}{2}\)×(-\(\frac{7}{4}\))
= \(\frac{9×(-7)}{2×4}\) = -\(\frac{63}{8}\)

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(ii) \(\frac{3}{10}\)×(-9)
= \((\frac{3}{10})  ×\frac{-9}{1}\) = \(\frac{3×(-9)}{10×1}\)= \(\frac{-27}{10}\)

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(iii) -\(\frac{6}{5}\)×\(\frac{9}{11}\)
= \(\frac{-6×9}{5×11}\) = -\(\frac{54}{55}\)

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(iv)\(\frac{3}{7}\)×(-\(\frac{2}{5}\))
= \(\frac{3×(-2)}{7×5}\) = \(-\frac{6}{35}\)

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(v)  \(\frac{3}{11}\)×\(\frac{2}{5}\)
= \(\frac{3×2}{11×5}\)= \(\frac{6}{55}\)

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(vi) \(\frac{3}{-5}\) ×\(\frac{-5}{3}\)
= \(\frac{3×(-5)}{(-5)×3}\) = \(\frac{-15}{-15}\)= 1