Question:
Find the odd one out in the series:
\[
G,\;K,\;M,\;Q,\;S,\;X
\]
Find the odd one out in the series:
\[
G,\;K,\;M,\;Q,\;S,\;X
\]
Show Hint
In alphabet series, always convert letters into position values. Hidden number patterns become easy to spot.
Updated On: Jul 15, 2026
- \(X\)
- \(S\)
- \(Q\)
- \(M\)
Show Solution
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The Correct Option is A
Solution and Explanation
Concept:
Convert each letter into its alphabetical position:
\[
G=7,\;K=11,\;M=13,\;Q=17,\;S=19,\;X=24
\]
Now observe:
\[
7,11,13,17,19,24
\]
Step 1: Identify the pattern.
These numbers are mostly prime numbers: \[ 7,\;11,\;13,\;17,\;19 \] All are prime.
Step 2: Check the remaining term.
For \(X\): \[ X=24 \] But: \[ 24=2^3 \times 3 \] which is not prime. Thus, \(X\) breaks the pattern. Hence, the odd one out is: \[ \boxed{X} \]
Step 1: Identify the pattern.
These numbers are mostly prime numbers: \[ 7,\;11,\;13,\;17,\;19 \] All are prime.
Step 2: Check the remaining term.
For \(X\): \[ X=24 \] But: \[ 24=2^3 \times 3 \] which is not prime. Thus, \(X\) breaks the pattern. Hence, the odd one out is: \[ \boxed{X} \]
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