
For mutual inductance in coplanar loops:
• Use the magnetic field from the larger loop and calculate flux through the smaller loop.
• Divide flux by the current to obtain mutual inductance.
\(M = \frac{\sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{2 \sqrt{2} \mu_0 R}{L^2}\)
\(M = \frac{2 \sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{\sqrt{2} \mu_0 R}{L^2}\)
\[ \phi = M i \]
\[ \phi = (BA) \]
\[ \phi = \pi R^2 \left( \frac{4\mu_0}{4\pi} \cdot i \cdot \frac{L}{2} \right) \sqrt{2} \]
\[ \implies M = \frac{2\sqrt{2} \mu_0 R^2}{L} \]
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]