Find the maximization of \( z = x + y \), under the following constraints:
\[
x - y \leq -1, -x + y \leq 0, x \geq 0, y \geq 0.
\]
Show Hint
In linear programming problems, solving the system of constraints often gives the vertices of the feasible region, where the maximum or minimum values occur.
We need to maximize \( z = x + y \), subject to the constraints:
\[
x - y \leq -1, -x + y \leq 0, x \geq 0, y \geq 0.
\]
We begin by graphing the constraints:
1. \( x - y \leq -1 \) represents a line with slope 1 and intercept -1.
2. \( -x + y \leq 0 \) represents a line with slope 1 and intercept 0.
3. \( x \geq 0 \) is the region to the right of the y-axis.
4. \( y \geq 0 \) is the region above the x-axis.
The feasible region is the area bounded by these lines. We can find the vertices of this region by solving the system of equations:
1. Solve \( x - y = -1 \) and \( -x + y = 0 \):
\[
x - y = -1 \text{(i)}
\]
\[
-x + y = 0 \text{(ii)}
\]
From (ii), \( x = y \). Substituting into (i):
\[
x - x = -1 $\Rightarrow$ 0 = -1,
\]
which is a contradiction, meaning there is no solution.
Next, solve for other pairs of constraints to determine the vertices.