Question:
Find the intercepts made by the line \(3x+4y-12=0\) on the axes:
Find the intercepts made by the line \(3x+4y-12=0\) on the axes:
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Set y=0 to find the x-intercept and x=0 to find the y-intercept.
Updated On: Jul 15, 2026
- 2 and 3
- 4 and 3
- 3 and 5
- None of these
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The Correct Option is B
Solution and Explanation
Step 1: Rewrite the line in intercept form.
The intercept form is \(\dfrac{x}{a}+\dfrac{y}{b}=1\), where a is the x-intercept and b is the y-intercept.
Step 2: Rearrange the given equation.
\(3x+4y=12\). Dividing both sides by 12: \(\dfrac{3x}{12}+\dfrac{4y}{12}=1 \Rightarrow \dfrac{x}{4}+\dfrac{y}{3}=1\).
Step 3: Read off the intercepts.
Comparing with the intercept form, \(a=4\) (x-intercept) and \(b=3\) (y-intercept).
Step 4: Final Answer.
The intercepts are 4 and 3, so option B is correct.
The intercept form is \(\dfrac{x}{a}+\dfrac{y}{b}=1\), where a is the x-intercept and b is the y-intercept.
Step 2: Rearrange the given equation.
\(3x+4y=12\). Dividing both sides by 12: \(\dfrac{3x}{12}+\dfrac{4y}{12}=1 \Rightarrow \dfrac{x}{4}+\dfrac{y}{3}=1\).
Step 3: Read off the intercepts.
Comparing with the intercept form, \(a=4\) (x-intercept) and \(b=3\) (y-intercept).
Step 4: Final Answer.
The intercepts are 4 and 3, so option B is correct.
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