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find tan1 circ tan2 circ tan3 circ cdots tan89 cir
Question:
Find \[ \tan1^\circ \tan2^\circ \tan3^\circ \cdots \tan89^\circ \]
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In trigonometric products, always check complementary angle pairing.
TG ICET - 2026
TG ICET
Updated On:
Jul 15, 2026
\(2\sqrt6\)
\(0\)
\(1\)
\(2\)
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The Correct Option is
C
Solution and Explanation
Use the identity: \[ \tan\theta \tan(90^\circ-\theta)=1 \] Pair terms: \[ \tan1^\circ \tan89^\circ=1 \] \[ \tan2^\circ \tan88^\circ=1 \] \[ \tan3^\circ \tan87^\circ=1 \] Similarly all pairs become \(1\). Middle term: \[ \tan45^\circ=1 \] So: \[ \tan1^\circ \tan2^\circ \cdots \tan89^\circ=1\times1\times1\cdots\times1=1 \] Thus, \[ \boxed{1} \]
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