A block of mass 5 kg starting from rest pulled up on a smooth incline plane making an angle of 30◦ with horizontal with an affective acceleration of 1 ms−2. The power delivered by the pulling force at t = 10 s from the starts is W. [use g=10 ms−2] (Calculate the nearest integer value)

The forces acting along the incline include:
Applying Newton’s second law along the incline:
\[ F - m g \sin \theta = m a. \]
Substitute the given values (\( m = 5 \, \text{kg}, g = 10 \, \text{m/s}^2, \sin 30^\circ = 0.5, a = 1 \, \text{m/s}^2 \)):
\[ F - 5 \cdot 10 \cdot 0.5 = 5 \cdot 1. \]
Simplify:
\[ F - 25 = 5 \implies F = 30 \, \text{N}. \]
Using the first equation of motion:
\[ v = u + a t. \]
Substitute \( u = 0, a = 1 \, \text{m/s}^2, t = 10 \, \text{s} \):
\[ v = 0 + 1 \cdot 10 = 10 \, \text{m/s}. \]
Power is the rate at which work is done, given by:
\[ P = F v. \]
Substitute \( F = 30 \, \text{N} \) and \( v = 10 \, \text{m/s} \):
\[ P = 30 \cdot 10 = 300 \, \text{W}. \]
The power delivered by the pulling force is \( 300 \, \text{W} \).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
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