Find: (i) 9 $\frac{3}{2}$ (ii) 32 $\frac{2}{5}$ (iii) 16 $\frac{3}{4}$ (iv) 125 - $\frac{1}{3}$

Question

Find: (i) 9  $\frac{3}{2}$  (ii) 32  $\frac{2}{5}$  (iii) 16  $\frac{3}{4}$  (iv) 125 - $\frac{1}{3}$

cdquestions Admin · Accepted Answer

(i) 9  $\frac{3}{2}$  = (9  $\frac{1}{2}$ )3  $\frac{1}{3}$ = (3) 3 = 27 (ii) 32  $\frac{2}{5}$  = (32  $\frac{1}{5}$ )2 = (2) 2 = 4 (iii) 16  $\frac{3}{4}$  = (16 $\frac{1}{4}$ )3 = (2) 3 = 8 (iv) 125 - $\frac{1}{3}$  =  $\frac{1}{(125)}\frac{1}{3}$  =  $\frac{1}{5}$

Length (in hours)	Number of lamps
300 − 400	14
400 − 500	56
500 − 600	60
600 − 700	86
700 − 800	74
800 − 900	62
900 − 1000	48

Length (in hours)	Number of lamps
300 − 400	14
400 − 500	56
500 − 600	60
600 − 700	86
700 − 800	74
800 − 900	62
900 − 1000	48

Find: (i) 9 \(\frac{3}{2}\) (ii) 32 \(\frac{2}{5}\) (iii) 16 \(\frac{3}{4}\) (iv) 125 -\(\frac{1}{3}\)

Solution and Explanation

Top CBSE Class IX Mathematics Questions

Top CBSE Class IX Questions