Step 1: Use the identity for \( a^3 + b^3 - c^3 \), if applicable.
But instead, compute the values numerically or via trigonometric symmetry.
Use approximation or calculator: \[ \sin 10^\circ \approx 0.1736 \Rightarrow \sin^3 10^\circ \approx 0.1736^3 = 0.0052 \] \[ \sin 50^\circ \approx 0.7660 \Rightarrow \sin^3 50^\circ \approx 0.4493 \] \[ \sin 70^\circ \approx 0.9397 \Rightarrow \sin^3 70^\circ \approx 0.8306 \] \[ \sin^3 10^\circ + \sin^3 50^\circ - \sin^3 70^\circ \approx 0.0052 + 0.4493 - 0.8306 = -0.3761 \approx -\dfrac{3}{8} \]
| List-I | List-II | ||
|---|---|---|---|
| (A) | $f(x) = \frac{|x+2|}{x+2} , x \ne -2 $ | (I) | $[\frac{1}{3} , 1 ]$ |
| (B) | $(x)=|[x]|,x \in [R$ | (II) | Z |
| (C) | $h(x) = |x - [x]| , x \in [R$ | (III) | W |
| (D) | $f(x) = \frac{1}{2 - \sin 3x} , x \in [R$ | (IV) | [0, 1) |
| (V) | { -1, 1} | ||
| List I | List II | ||
|---|---|---|---|
| (A) | $\lambda=8, \mu \neq 15$ | 1. | Infinitely many solutions |
| (B) | $\lambda \neq 8, \mu \in R$ | 2. | No solution |
| (C) | $\lambda=8, \mu=15$ | 3. | Unique solution |
If \(\cos \alpha + \cos \beta + \cos \gamma = \sin \alpha + \sin \beta + \sin \gamma = 0,\) then evaluate \((\cos^3 \alpha + \cos^3 \beta + \cos^3 \gamma)^2 + (\sin^3 \alpha + \sin^3 \beta + \sin^3 \gamma)^2 =\)