Question:
Ethyl iodide when heated with sodium in dry ether gives pure
Ethyl iodide when heated with sodium in dry ether gives pure
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Wurtz reaction gives symmetrical alkanes with even number of carbons.
Updated On: Apr 7, 2026
- C\(_4\)H\(_{10}\)
- C\(_2\)H\(_6\)
- C\(_3\)H\(_8\)
- C\(_2\)H\(_5\)OH
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
This is Wurtz reaction.
Step 2: Detailed Explanation:
2C\(_2\)H\(_5\)I + 2Na \(\rightarrow\) C\(_4\)H\(_{10}\) + 2NaI
Step 3: Final Answer:
Product is butane (C\(_4\)H\(_{10}\)).
This is Wurtz reaction.
Step 2: Detailed Explanation:
2C\(_2\)H\(_5\)I + 2Na \(\rightarrow\) C\(_4\)H\(_{10}\) + 2NaI
Step 3: Final Answer:
Product is butane (C\(_4\)H\(_{10}\)).
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