Comprehension

EMPLOYEE Table

Emp No	Ename	Salary	Bonus	DeptId
101	Aaliya	10000	234	D02
102	Kritika	60000	123	D01
103	Shabbir	45000	566	D01
104	Gurpreet	19000	565	D04
105	Joseph	34000	875	D03
106	Sanya	48000	695	D02
107	Vergeese	15000	NULL	D01
108	Nachaobi	29000	NULL	D05
109	Daribha	42000	NULL	D04
110	Tanya	50000	467	D05

What will be the output of the SQL query based on above EM PLOYEE table?

Question: 1

SELECT COUNT(*) FROM EMPLOYEE WHERE BONUS IS NULL;

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In SQL, the COUNT function counts the number of non-NULL values. To count rows with NULL values, use the IS NULL condition in the WHERE clause.

Updated On: Feb 13, 2026

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The Correct Option is C

Solution and Explanation

The SQL query counts the number of rows where the value in the "Bonus" column is NULL. Based on the table, there are four employees (Vergeese, Nachaobi, Daribha, and Tanya) who have NULL in the "Bonus" column. Therefore, the correct answer is 4.

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Question: 2

SELECT AVG(Salary) FROM EMPLOYEE WHERE Ename like ’ anya’;

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The LIKE operator in SQL is used to match patterns in string data. In this case, 'anya' matches any name ending with "anya," where the underscore represents a single character.

Updated On: Feb 13, 2026

48000
47000
49000
50000

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The Correct Option is D

Solution and Explanation

The SQL query is calculating the average salary of employees whose names match the pattern 'anya', which means any name that ends with "anya." The matching names are "Aaliya" and "Tanya." Their salaries are 10000 and 50000 respectively. The average salary is \((10000 + 50000) / 2 = 60000 / 2 = 50000\). Therefore, the correct answer is 50000.

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Question: 3

SELECT SUM(Bonus) FROM EMPLOYEE WHERE Ename LIKE ’%a’ AND Salary > 45000;

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The LIKE operator with '%' at the end is used to find values that end with a certain string. In this case, '%a' matches any name that ends with "a."

Updated On: Feb 13, 2026

1185
1265
1275
1285

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The Correct Option is B

Solution and Explanation

The SQL query is calculating the sum of the bonuses where the employee's name ends with "a" and the salary is greater than 45000. The employees matching the condition are Kritika (Bonus: 123) and Tanya (Bonus: 467). Thus, the sum is \( 123 + 467 + 875 = 1265 \). Therefore, the correct answer is 1265.

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Question: 4

SELECT MIN(Salary) FROM EMPLOYEE WHERE DeptId = ’D01’;

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The MIN() function returns the smallest value of the selected column. In this case, the smallest salary in department 'D01' is 15000.

Updated On: Feb 13, 2026

60000
15000
30000
45000

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The Correct Option is B

Solution and Explanation

The SQL query is finding the minimum salary in the department with DeptId 'D01'. The employees in 'D01' are Kritika (60000), Shabbir (45000), and Vergeese (15000). The minimum salary among these is 15000. Therefore, the correct answer is 15000.

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Question: 5

SELECT MAX(Salary) FROM EMPLOYEE WHERE Bonus IS NOT NULL AND DeptId IN (’D01’, ’D02’);

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The MAX() function returns the highest value from the selected column. In this case, it returns the highest salary from the employees in 'D01' and 'D02' with non-NULL bonuses.

Updated On: Feb 13, 2026

48000
50000
60000
45000

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The Correct Option is A

Solution and Explanation

The SQL query is finding the maximum salary for employees whose bonus is not NULL and whose department ID is either 'D01' or 'D02'. The employees in these departments are:
- Kritika (D01, Salary: 60000, Bonus: 123)
- Shabbir (D01, Salary: 45000, Bonus: 566)
- Aaliya (D02, Salary: 10000, Bonus: 234)
- Sanya (D02, Salary: 48000, Bonus: 695)
The highest salary among these is 48000. Therefore, the correct answer is 48000.

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	List - I		List - II
A	Streptokinase	I	Blood-Cholestrol lowering agents
B	Cyclosporin	II	Clot Buster
C	Statins	III	Propionibacterium sharmanii
D	Swiss Cheese	IV	Immuno suppressive agent

SELECT COUNT(*) FROM EMPLOYEE WHERE BONUS IS NULL;

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The Correct Option is C

Solution and Explanation

SELECT AVG(Salary) FROM EMPLOYEE WHERE Ename like ’ anya’;

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The Correct Option is D

Solution and Explanation

SELECT SUM(Bonus) FROM EMPLOYEE WHERE Ename LIKE ’%a’ AND Salary > 45000;

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The Correct Option is B

Solution and Explanation

SELECT MIN(Salary) FROM EMPLOYEE WHERE DeptId = ’D01’;

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The Correct Option is B

Solution and Explanation

SELECT MAX(Salary) FROM EMPLOYEE WHERE Bonus IS NOT NULL AND DeptId IN (’D01’, ’D02’);

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The Correct Option is A

Solution and Explanation

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