Question:

Elimination after 4 half lives in first order kinetics is?

Show Hint

Remaining is (1/2) raised to the number of half lives.
Updated On: Jun 24, 2026
  • 84%
  • 93%
  • 80.5%
  • 4.75%
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: In first order kinetics a constant fraction of drug is eliminated per unit time, so each half life removes half of whatever remains.

Step 2: Track the fraction remaining: after 1 half life 50 percent is gone, after 2 half lives 75 percent, after 3 half lives 87.5 percent, and after 4 half lives the amount remaining is \(\left(\tfrac{1}{2}\right)^4 = \tfrac{1}{16}\), which is about 6.25 percent.

Step 3: Therefore the amount eliminated is \(100 - 6.25 = 93.75\) percent, which rounds to about 93 percent.

Answer: 93 percent.
Was this answer helpful?
0
0