Step 1: In first order kinetics a constant fraction of drug is eliminated per unit time, so each half life removes half of whatever remains.
Step 2: Track the fraction remaining: after 1 half life 50 percent is gone, after 2 half lives 75 percent, after 3 half lives 87.5 percent, and after 4 half lives the amount remaining is \(\left(\tfrac{1}{2}\right)^4 = \tfrac{1}{16}\), which is about 6.25 percent.
Step 3: Therefore the amount eliminated is \(100 - 6.25 = 93.75\) percent, which rounds to about 93 percent.
Answer: 93 percent.