Elevation in the boiling point for 1 molar solution of glucose is 2 K. The depression in the freezing point for 2 molal solution of glucose in the same solvent is 2 K. The relation between \(K_b\) and \(K_f\) is
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- \(K_b = K_f\)
- \(K_b = 0.5\,K_f\)
- \(K_b = 1.5\,K_f\)
- \(K_b = 2\,K_f\)
The Correct Option is D
Solution and Explanation
\(\Delta T_f = K_f \times m\): 2 = \(K_f \times 2\), so \(K_f = 1\ \text{K kg mol}^{-1}\).
Hence \(K_b / K_f = 2\), i.e. \(K_b = 2K_f\).
Answer: (4) \(K_b = 2\,K_f\)
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