Question:
Electric flux through cube of side 'a' enclosing charge 'q' is:
Electric flux through cube of side 'a' enclosing charge 'q' is:
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Gauss's Law: Total flux = enclosed charge over epsilon-naught.
Updated On: Jun 6, 2026
- $q/a^2$
- $q/\epsilon_0$
- Zero
- $2q/(a\epsilon_0)$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Gauss's Law: $\Phi = \frac{q_{enc}}{\epsilon_0}$.
Step 2: Meaning
Flux depends only on the charge enclosed, not the shape/size of the surface.
Step 3: Analysis
For any closed surface enclosing a charge $q$, the total flux is $q/\epsilon_0$.
Step 4: Conclusion
Flux is $q/\epsilon_0$.
Final Answer: (B)
Gauss's Law: $\Phi = \frac{q_{enc}}{\epsilon_0}$.
Step 2: Meaning
Flux depends only on the charge enclosed, not the shape/size of the surface.
Step 3: Analysis
For any closed surface enclosing a charge $q$, the total flux is $q/\epsilon_0$.
Step 4: Conclusion
Flux is $q/\epsilon_0$.
Final Answer: (B)
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