Question

Efficiency of an reversible engine is given by

• A. Clapeyron equation
• B. Carnot theorem
• C. Claussius Clapeyron equation
• D. Gibbs-Helmholtz

Answer 1

The Correct Option is B

The question asks about the efficiency of a reversible engine, and the correct concept or theorem associated with it. This is a question related to thermodynamics, which is crucial in many fields, including pharmaceutical engineering.

To find the efficiency of a reversible engine, we refer to the Carnot theorem. The Carnot theorem states that no engine operating between two heat reservoirs can be more efficient than a Carnot engine operating between those same reservoirs. The efficiency of a Carnot engine depends solely on the temperatures of the two reservoirs.

The efficiency \( \eta \) of a Carnot engine is given by the formula:

\(\eta = 1 - \frac{T_C}{T_H}\)

where \( T_H \) is the absolute temperature of the hot reservoir, and \( T_C \) is the absolute temperature of the cold reservoir.

Now, let us briefly explore why other options are incorrect:

• Clapeyron equation: This equation relates the pressure, volume, and temperature of a perfect gas and is not directly related to the efficiency of an engine.
• Claussius Clapeyron equation: This is useful for understanding phase transitions, such as boiling and condensation, and describes the relation between pressure and temperature during phase changes.
• Gibbs-Helmholtz equation: This equation is used to determine how the Gibbs free energy and enthalpy change with temperature. It is not directly related to the efficiency of heat engines.

Thus, the correct answer to the question regarding the efficiency of a reversible engine is attributed to the Carnot theorem.