Step 1: Set the surface energy balance over the diurnal cycle.
At the land surface, the net radiation \(R_n = (S_\downarrow - S_\uparrow) + (L_\downarrow - L_\uparrow)\) drives sensible (\(H\)) and latent (\(LE\)) heat fluxes and ground heat flux (\(G\)). After sunset \(S_\downarrow \approx 0\), so \(R_n<0\) due to strong longwave loss \(L_\uparrow\). Hence, \(H\) becomes negative (air is cooled by the surface), and the near‐surface layer cools continuously through the night.
Step 2: Nighttime boundary layer evolution.
Radiative cooling at the ground produces a stable surface layer (temperature increases with height). Turbulence weakens, so mixing is small and 2 m air closely follows surface cooling. This cooling proceeds monotonically through the night if sky is clear and winds are light.
Step 3: Why minimum occurs \(near\ sunrise\) and not at midnight.
Cooling continues as long as \(R_n<0\). The transition to net heating starts only after the sun rises high enough for \(S_\downarrow\) to offset longwave loss—this happens \emph{after} sunrise. Therefore the lowest 2 m temperature typically happens just before/at sunrise, with a small lag depending on clouds/wind. Midnight is earlier in the cooling period, so temperature is still dropping toward its minimum.
Step 4: Role of local factors (for completeness).
Clouds reduce longwave loss (warmer night); wind increases mixing (less cooling). Both can shift the exact timing slightly, but in tropical clear-sky land locations the canonical minimum remains just before sunrise.
Final Answer:
\[ \boxed{\text{At sunrise}} \]


An electricity utility company charges ₹7 per kWh. If a 40-watt desk light is left on for 10 hours each night for 180 days, what would be the cost of energy consumption? If the desk light is on for 2 more hours each night for the 180 days, what would be the percentage-increase in the cost of energy consumption?
In the context of the given figure, which one of the following options correctly represents the entries in the blocks labelled (i), (ii), (iii), and (iv), respectively?

A bag contains Violet (V), Yellow (Y), Red (R), and Green (G) balls. On counting them, the following results are obtained:
(i) The sum of Yellow balls and twice the number of Violet balls is 50.
(ii) The sum of Violet and Green balls is 50.
(iii) The sum of Yellow and Red balls is 50.
(iv) The sum of Violet and twice the number of Red balls is 50.
Which one of the following Pie charts correctly represents the balls in the bag?