Let the population at the beginning of the first year be P.
At the end of the first year, the population increases by 5%, so it becomes:
\[ P \times 1.05 \]
At the end of the second year, the population again increases by 5%, so it becomes:
\[ P \times 1.05 \times 1.05 = P \times 1.05^2 \]
We are given that the population at the end of the second year is 9975:
\[ P \times 1.05^2 = 9975 \]
\[ P = \frac{9975}{1.1025} = 10000 \]
Thus, the population size at the beginning of the first year is 10,000.
A positive integer $m$ is increased by 20% and the resulting number is 1080. Then the integer $m$ is
A software company lays off 40% of its employees. Among the laid-off employees, 20% are developers. The percentage of laid-off developers from the total employees of the company is
If one-fourth of a number exceeds 20% of the number by 10, then the number is
Arun’s present age in years is 40% of Barun’s. In another few years, Arun’s age will be half of Barun’s. By what percentage will Barun’s age increase during this period?