Question

Statement A: The success rate of moving from written test to interview stage for males was worse than for females in 2003.
Statement B: The success rate of moving from written test to interview stage for females was better in 2002 than in 2003.

• A. Only Statement A is true.
• B. Only Statement B is true.
• C. Both the Statements are true.
• D. Neither of the two Statements is true.
• A. Only Statement A is true.
• B. Only Statement B is true.
• C. Both the Statements are true.
• D. Neither of the two Statements is true.
• A. Only Statement A is true.
• B. Only Statement B is true.
• C. Both the Statements are true.
• D. Neither of the two Statements is true.

Answer 1

The Correct Option is D

Step 1: Understand the success rate.
The success rate of moving from the written test to the interview stage tells us what part of the students who sat the written test were called for interview.
So the rate is the number called for interview divided by the number who appeared for the written test. The number of applications and the number finally selected play no part here.
"Better" means a higher rate and "worse" means a lower rate.

Step 2: Find the rates for males and females in 2003.
Males in 2003: \( \dfrac{637}{60133} \times 100 \approx 1.059\% \).
Females in 2003: \( \dfrac{399}{40763} \times 100 \approx 0.979\% \).
So the male rate is higher than the female rate in 2003.

Step 3: Check Statement A.
Statement A says the male rate was worse (lower) than the female rate in 2003. We found \(1.059\% > 0.979\%\), so the male rate was better, not worse. Statement A is FALSE.

Step 4: Find the female rates for 2002 and 2003.
Females in 2002: \( \dfrac{138}{15389} \times 100 \approx 0.897\% \).
Females in 2003: \( 0.979\% \) from Step 2.

Step 5: Check Statement B.
Statement B says the female rate was better in 2002 than in 2003. But \(0.897\% < 0.979\%\), so the 2002 rate was lower. The rate actually improved in 2003. Statement B is FALSE.

Step 6: Match with the options.
Option (1) needs A to be true, but A is false. Option (2) needs B to be true, but B is false. Option (3) needs both to be true, which is wrong. Option (4) says neither is true, which matches our result.

Final Answer:
Both statements are false, so the correct choice is option (4). \[ \boxed{\text{Option (4)}} \]

Answer 2

Step 1: Read what each statement compares.
Both statements are about 2002 only, so we use the 2002 rows of the table.
In Statement A, the students who bought application forms are the ones counted under Number of Applications. The proportion is the number selected divided by the number of applications.
In Statement B, the success rate among those called for interview is the number selected divided by the number called for interview.

Step 2: Work out the two proportions for Statement A.
Females in 2002: \( \dfrac{48}{19236} \times 100 \approx 0.2495\% \).
Males in 2002: \( \dfrac{171}{61205} \times 100 \approx 0.2794\% \).
The male proportion is slightly higher.

Step 3: Check Statement A.
Statement A says the female proportion was higher than the male proportion. But \(0.2495\% < 0.2794\%\), so the female proportion was lower. Statement A is FALSE.

Step 4: Work out the interview success rates for Statement B.
Males in 2002: \( \dfrac{171}{684} \times 100 = 25\% \).
Females in 2002: \( \dfrac{48}{138} \times 100 \approx 34.78\% \).
So among those called for interview, females did better.

Step 5: Check Statement B.
Statement B says males had the greater success rate. We found \(25\% < 34.78\%\), so females had the greater rate. Statement B is FALSE.

Step 6: Match with the options.
Option (1) needs A true, but A is false. Option (2) needs B true, but B is false. Option (3) needs both true, which is wrong. Option (4), neither statement is true, is the one that fits.

Final Answer:
Both statements are false, so the correct choice is option (4). \[ \boxed{\text{Option (4)}} \]

Answer 3

Step 1: Decide who an absentee is.
A student who applied but did not appear for the written test is an absentee.
So the number of absentees is the Number of Applications minus the number who appeared for the written test. The percentage of absentees is that number divided by the Number of Applications.

Step 2: Absentee percentage for females in 2002 and 2003.
2002: absentees \( = 19236 - 15389 = 3847 \), so the percentage is \( \dfrac{3847}{19236} \times 100 \approx 20.0\% \).
2003: absentees \( = 45292 - 40763 = 4529 \), so the percentage is \( \dfrac{4529}{45292} \times 100 \approx 10.0\% \).

Step 3: Check Statement A.
The female absentee percentage went from about 20% in 2002 to about 10% in 2003. That is a fall, so Statement A is TRUE.

Step 4: Absentee percentage for males in 2003.
Absentees \( = 63298 - 60133 = 3165 \).
Percentage \( = \dfrac{3165}{63298} \times 100 \approx 5.0\% \).
For females in 2003 we already found about 10.0%.

Step 5: Check Statement B.
Statement B says the male percentage was larger than the female percentage in 2003. But \(5.0\% < 10.0\%\), so males were absent less often than females. Statement B is FALSE.

Step 6: Match with the options.
A is true and B is false. That is exactly option (1), Only Statement A is true.
Option (2) is wrong because B is false. Option (3) is wrong because B is false. Option (4) is wrong because A is true.

Final Answer:
Only Statement A is true, which is option (1). \[ \boxed{\text{Option (1)}} \]