Differentiate between the following pairs based on the criteria given in the bracket:
(a) Acetic acid and Sulphuric acid (number of replaceable hydrogen ion per molecule)
(b) Electrolyte and Metallic conductor (the particles conducting electricity)
(a) Acetic acid and Sulphuric acid (number of replaceable hydrogen ion per molecule)
(b) Electrolyte and Metallic conductor (the particles conducting electricity)
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Solution and Explanation
(a) Acetic acid vs. Sulphuric acid: Acetic acid ((CH_3COOH)): It is monobasic, meaning it has one replaceable hydrogen ion per molecule. Sulphuric acid ((H_2SO_4)): It is dibasic, meaning it has two replaceable hydrogen ions per molecule.
(b) Electrolyte vs. Metallic conductor: Electrolyte: The particles conducting electricity are mobile ions (cations and anions). Metallic conductor: The particles conducting electricity are free electrons.
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(Zn + 4HNO_3 Zn(NO_3)_2 + 2H_2O + 2NO_2)
32.5 g of zinc reacts with concentrated nitric acid as given in the above equation.
(a) How many moles of zinc was required in the reaction?
(b) Find the mass of nitric acid needed to react with 32.5 g of zinc.
(c) Find the volume of nitrogen dioxide liberated in (b).
(Atomic weight: H = 1, N = 14, O = 16, Zn = 65)
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