Question:

Diamond has a three dimensional structure of C atoms formed by covalent bonds. The structure of diamond has face centred cubic lattice where 50% of the tetrahedral voids are also occupied by carbon atoms. The number of carbon atoms present per unit cell of diamond is ____________.

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An FCC lattice has 4 atoms per unit cell and 8 tetrahedral voids; half of the voids are occupied.
Updated On: Nov 4, 2026
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Correct Answer: 8

Solution and Explanation

FCC lattice: atoms at 8 corners and 6 face centres give \(8\times\frac{1}{8}+6\times\frac{1}{2}=4\) atoms per unit cell.
Number of tetrahedral voids = 2 per atom = \(2\times4 = 8\).
50% of the tetrahedral voids are occupied: \(0.5\times 8 = 4\) atoms.
Total C atoms per unit cell = 4 + 4 = 8.
Answer: 8
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