D(+)-Glucose reacts with hydroxylamine and forms oxime. The structure of oxime would be:
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When glucose reacts with hydroxylamine, the aldehyde group (-CHO) reacts to form an oxime (-C=NOH) in which the nitrogen atom is bonded to the carbon of the aldehyde group.
When glucose reacts with hydroxylamine, it forms an oxime. In this reaction, the aldehyde group (-CHO) in glucose reacts with hydroxylamine (NH₂OH) to form the oxime group (-C=NOH). The correct structure of the oxime formed from glucose would be:
The structure would show the oxime group (-C=NOH) replacing the aldehyde group, and the rest of the glucose structure remains the same.