Question:
\(\dfrac{d}{dx}\!\left(\dfrac{1}{4}\sec4x\right)=\) ?
\(\dfrac{d}{dx}\!\left(\dfrac{1}{4}\sec4x\right)=\) ?
Show Hint
For $\sec(kx)$, derivative is $k\,\sec(kx)\tan(kx)$.
Updated On: Oct 17, 2025
- \(\sec4x\cdot\tan4x\)
- \(\sec^{2}4x\)
- \(\tan^{2}4x\)
- \(\dfrac{1}{16}\sec4x\cdot\tan4x\)
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
\[
\frac{d}{dx}\!\left(\frac14\sec4x\right)=\frac14\cdot (\sec4x\tan4x)\cdot 4=\sec4x\tan4x.
\]
Was this answer helpful?
0
0
Top Bihar Board XII Mathematics Questions
- \(\frac{d}{dx} \left(\sec^2 x - \tan^2 x\right)\)
- \(\frac{d}{dx} \left( e^{2x} + 2e^x \right)\)
- \(\frac{d}{dx} \left[ \lim_{x \to a} \frac{x^n + a^n}{x + a} \right] \)
- \(\frac{d}{dx} \left( \sin^{-1} 2x \right)\)
- \(\frac{d}{dx} \left[ (x+2)(x^2 - 2x + 4) \right] \)
View More Questions
Top Bihar Board XII Chain Rule Questions
- \(\frac{d}{dx} \left[ 2\sqrt{x} \right] \)
- \(\frac{d}{dx} \left[ e^{x^2} \right] \)
- \(\frac{d}{dx} \left( \cos(\pi x + \sin \pi x) \right) \)
- \(\dfrac{d}{dx}\big(2\cos \tfrac{3x}{4}\big)=\) ?
\(\dfrac{d}{dx}\big(e^{x}+\cos5x\big)=\) ?
View More Questions
Top Bihar Board XII Questions
- Which metal was first used by humans?
- Where is the Harappan site called Shortughai located?
- Where has the evidence of dockyard been found from Indus Valley Civilization?
- Which is referred to as Meluhha in Mesopotamian texts?
- Where have miniature pots of faience probably used as perfume bottles been found?
View More Questions