Question:

\[ \cos 6^\circ \sin 24^\circ \cos 72^\circ= \]

Show Hint

For products of trigonometric functions, use product-to-sum identities to simplify quickly.
  • \(\frac{1}{4}\)
  • \(-\frac{1}{8}\)
  • \(-\frac{1}{4}\)
  • \(\frac{1}{8}\)
Show Solution
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The Correct Option is D

Solution and Explanation

Concept: Use product-to-sum identities and known trigonometric angle relations.

Step 1:
Given: \[ \cos 6^\circ \sin 24^\circ \cos 72^\circ \]

Step 2:
Use product-to-sum identity: \[ 2\sin A\cos B=\sin(A+B)+\sin(A-B) \] First combine: \[ 2\sin 24^\circ \cos 72^\circ = \sin 96^\circ+\sin(-48^\circ) \] \[ =\sin 96^\circ-\sin 48^\circ \]

Step 3:
Now multiply with \(\cos6^\circ\).
Using standard trigonometric simplification, the complete product reduces to: \[ \frac{1}{8} \] Therefore, \[ \boxed{\frac{1}{8}} \]
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