Step 1: Identify compounds \(A,\;B,\;C,\;D\).
\[
3\mathrm{C_2H_2}
\rightarrow
\boxed{\mathrm{C_6H_6}}
\]
Hence,
\[
A=\text{Benzene}
\]
\[
\mathrm{C_6H_6}
\xrightarrow[\mathrm{AlCl_3}]{\mathrm{CH_3Cl}}
\boxed{\mathrm{C_6H_5CH_3}}
\]
Thus,
\[
B=\text{Toluene}
\]
Side-chain chlorination with two moles of chlorine gives
\[
\boxed{\mathrm{C_6H_5CHCl_2}}
\]
Hydrolysis of benzal chloride gives
\[
\boxed{\mathrm{C_6H_5CHO}}
\]
Therefore,
\[
D=\text{Benzaldehyde}
\]
Step 2: Identify the method which cannot prepare benzaldehyde.
Benzaldehyde can be prepared by
\[
\boxed{\text{Etard reaction}}
\]
\[
\boxed{\text{Rosenmund reaction}}
\]
\[
\boxed{\text{Gattermann--Koch reaction}}
\]
Friedel--Crafts reaction introduces alkyl or acyl groups into benzene but does not directly prepare benzaldehyde.
Hence,
\[
\boxed{(B)}
\]
is the correct answer.