Consider the given chemical reaction :
Product ''A'' is :
Product ''A'' is :
- picric acid
- oxalic acid
- acetic acid
- adipic acid
The Correct Option is D
Approach Solution - 1
The reaction of cyclohexane with potassium permanganate (\(\text{KMnO}_4\)) in an acidic medium (\(\text{H}_2\text{SO}_4\)) and heat results in the oxidation of cyclohexane to adipic acid.
Step 1: Oxidation of cyclohexane
Cyclohexane (\(\text{C}_6\text{H}_{12}\)) undergoes oxidation in the presence of \(\text{KMnO}_4\) and \(\text{H}_2\text{SO}_4\).
- The \(\text{KMnO}_4\) oxidizes the \(-\text{CH}_2-\) groups in cyclohexane to carboxylic acid (\(-\text{COOH}\)) groups.
- This results in the formation of adipic acid (\(\text{HOOC} - (\text{CH}_2)_4 - \text{COOH}\)).
\[\text{C}_6\text{H}_{12} \rightarrow [\text{KMnO}_4, \text{H}_2\text{SO}_4, \text{Heat}] \text{HOOC} - (\text{CH}_2)_4 - \text{COOH} \, (\text{Adipic Acid})\]
Step 2: Conclusion
The product \(A\) is adipic acid.
Final Answer: (4).
Approach Solution -2
Cyclohexene is oxidized by hot acidic potassium permanganate (KMnO₄ + H₂SO₄ + heat).
Step 2: Nature of the reaction.
Hot, concentrated, acidic KMnO₄ is a strong oxidizing agent. It cleaves the carbon–carbon double bond of alkenes completely, converting both carbons of the double bond into carboxylic acid groups if possible.
Step 3: Apply oxidation on cyclohexene.
Cyclohexene (C₆H₁₀) contains a double bond within a six-membered ring. When oxidized under these strong conditions, the ring is cleaved at the double bond, and each carbon of the double bond is converted into a carboxylic acid (-COOH).
Step 4: Product formed.
Thus, the product formed is a dicarboxylic acid with six carbons — adipic acid (hexanedioic acid).
Step 5: Final Answer.
The product "A" is adipic acid.
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