The function \(f(x)\) is defined as:
\[ f(x) = \begin{cases} 3-x, & \text{if } x \leq 0 \\ x^2 + 2, & \text{if } x \geq 0 \end{cases} \]
Since \(-3 \leq 0\), we use the first piece of the function: \(f(x) = 3-x\).
Substitute \(x = -3\) into the expression:
\[f(-3) = 3 - (-3) = 3 + 3 = 6\]
Thus, the value of \(f(-3)\) is 6.
Consider two distinct positive numbers \( m, n \) with \( m > n \). Let \[ x = n^{\log_n m}, \quad y = m^{\log_m n}. \] The relation between \( x \) and \( y \) is -
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.