Question:
Consider the following pairs of solution which will be isotonic at the same temperature. The number of pairs of solutions is/are......
A. 1 M aq. NaCl and 2 M aq. Urea
B. 1 M aq. CaCl2 and 1.5 M aq. KCl
C. 1.5 M aq. AlCl3 and 2 M aq. Na2SO4
D. 2.5 M aq. KCl and 1 M aq. Al2(SO4)3
Consider the following pairs of solution which will be isotonic at the same temperature. The number of pairs of solutions is/are......
A. 1 M aq. NaCl and 2 M aq. Urea
B. 1 M aq. CaCl2 and 1.5 M aq. KCl
C. 1.5 M aq. AlCl3 and 2 M aq. Na2SO4
D. 2.5 M aq. KCl and 1 M aq. Al2(SO4)3
A. 1 M aq. NaCl and 2 M aq. Urea
B. 1 M aq. CaCl2 and 1.5 M aq. KCl
C. 1.5 M aq. AlCl3 and 2 M aq. Na2SO4
D. 2.5 M aq. KCl and 1 M aq. Al2(SO4)3
Updated On: Feb 20, 2026
Show Solution
Verified By Collegedunia
Correct Answer: 4
Approach Solution - 1
Isotonic Solution Analysis
Isotonic solutions have the same osmotic pressure. Osmotic pressure is directly proportional to the concentration of solute particles. Therefore, isotonic solutions have the same concentration of solute particles. We need to determine the concentration of particles in each solution, considering dissociation of ionic compounds.
- A. \( \text{NaCl} \) dissociates into 2 ions (\( \text{Na}^+ \) and \( \text{Cl}^- \)). So, 1 M \( \text{NaCl} \) gives \( 1 \text{ M} \times 2 = 2 \text{ M} \) ions. Urea does not dissociate, so 2 M urea remains 2 M particles. These solutions are isotonic.
- B. \( \text{CaCl}_2 \) dissociates into 3 ions (\( \text{Ca}^{2+} \) and \( 2\text{Cl}^- \)). So, 1 M \( \text{CaCl}_2 \) gives \( 1 \text{ M} \times 3 = 3 \text{ M} \) ions. \( \text{KCl} \) dissociates into 2 ions (\( \text{K}^+ \) and \( \text{Cl}^- \)). So, 1.5 M \( \text{KCl} \) gives \( 1.5 \text{ M} \times 2 = 3 \text{ M} \) ions. These solutions are isotonic.
- C. \( \text{AlCl}_3 \) dissociates into 4 ions (\( \text{Al}^{3+} \) and \( 3\text{Cl}^- \)). So, 1.5 M \( \text{AlCl}_3 \) gives \( 1.5 \text{ M} \times 4 = 6 \text{ M} \) ions. \( \text{Na}_2\text{SO}_4 \) dissociates into 3 ions (\( 2\text{Na}^+ \) and \( \text{SO}_4^{2-} \)). So, 2 M \( \text{Na}_2\text{SO}_4 \) gives \( 2 \text{ M} \times 3 = 6 \text{ M} \) ions. These solutions are isotonic.
- D. \( \text{KCl} \) dissociates into 2 ions (\( \text{K}^+ \) and \( \text{Cl}^- \)). So, 2.5 M \( \text{KCl} \) gives \( 2.5 \text{ M} \times 2 = 5 \text{ M} \) ions. \( \text{Al}_2\text{(SO}_4)_3 \) dissociates into 5 ions (\( 2\text{Al}^{3+} \) and \( 3\text{SO}_4^{2-} \)). So, 1 M \( \text{Al}_2\text{(SO}_4)_3 \) gives \( 1 \text{ M} \times 5 = 5 \text{ M} \) ions. These solutions are isotonic.
Conclusion:
All four pairs are isotonic. Therefore, the number of isotonic pairs is 4.
Was this answer helpful?
0
0
Show Solution
Verified By Collegedunia
Approach Solution -2
For two solutions to be isotonic, the total number of ions should be the same. Checking the pairs for ion concentration:
- A: 1 M NaCl gives 2 ions, and 2 M Urea gives 2 ions — isotonic.
- B: 1 M CaCl\(_2\) gives 3 ions, and 1.5 M KCl gives 3 ions — isotonic.
- C: 1.5 M AlCl\(_3\) gives 6 ions, and 2 M Na\(_2\)SO\(_4\) gives 6 ions — isotonic.
- D: 2.5 M KCl gives 5 ions, and 1 M Al\(_2\)(SO\(_4\))\(_3\) gives 5 ions — isotonic.
Thus, all 4 pairs are isotonic.
- A: 1 M NaCl gives 2 ions, and 2 M Urea gives 2 ions — isotonic.
- B: 1 M CaCl\(_2\) gives 3 ions, and 1.5 M KCl gives 3 ions — isotonic.
- C: 1.5 M AlCl\(_3\) gives 6 ions, and 2 M Na\(_2\)SO\(_4\) gives 6 ions — isotonic.
- D: 2.5 M KCl gives 5 ions, and 1 M Al\(_2\)(SO\(_4\))\(_3\) gives 5 ions — isotonic.
Thus, all 4 pairs are isotonic.
Was this answer helpful?
0
0
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
View More Questions
Top JEE Main Solutions Questions
- What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg?
(Assume dilute solution is being formed)
Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is 180 g mol–1 . - Solubility of \(Ca_3(PO_4)_2\) in \(100\) \(mL\) of pure water is \(W\) gm. Find out \(K_{sp}\) of \(Ca_3(PO_4)_2\) is: (M: Molecular mass of \(Ca_3(PO_4)_2\))
- We are given with three NaCl samples and their Van't Hoff factors. Which is correct option ?
Sample Van't Haff Factor Sample - 1 (0.1 M) \(i_1\) Sample - 2 (0.01 M) \(i_2\) Sample - 3 (0.001 M) \(i_2\) - Ethylene glycol of \(x\) \(kg\) is mixed with \(18.6\) \(kg\) of solvent, \(24 °C\) depression in freezing point takes place. Calculate value of \(x\). (Given: \(K_1\) = \(1.6 °C/molal\) M.W. of ethylene glycol = \(62\) \(g/mol\))
- $\text{Volume of } 3 \, \text{M NaOH (formula weight 40 g mol}^{-1}\text{) which can be prepared from } 84 \, \text{g of NaOH is } \_\_\_\_\_ \times 10^{-1} \, \text{dm}^3.$
View More Questions
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
View More Questions