Consider the following ionization enthalpies of two elements ‘A’ and ‘B’.
Element Ionization enthalpy (kJ/mol) 1st 2nd 3rd A 899 1757 14847 B 737 1450 7731
Which of the following statements is correct ?
| Element | Ionization enthalpy (kJ/mol) | ||
| 1st | 2nd | 3rd | |
| A | 899 | 1757 | 14847 |
| B | 737 | 1450 | 7731 |
Show Hint
- Both ‘A’ and ‘B’ belong to group-1 where ‘B’ comes below ‘A’.
- Both ‘A’ and ‘B’ belong to group-1 where ‘A’ comes below ‘B’.
- Both ‘A’ and ‘B’ belong to group-2 where ‘B’ comes below ‘A’.
- Both ‘A’ and ‘B’ belong to group-2 where ‘A’ comes below ‘B’.
The Correct Option is C
Solution and Explanation
Ionization enthalpy decreases down a group. A (899, 1757) has higher values than B (737, 1450), so A is above B, i.e. B comes below A (A = Be, 899.5; B = Mg, 737.7).
Answer: (3) Both ‘A’ and ‘B’ belong to group-2 where ‘B’ comes below ‘A’.
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