The cache is direct-mapped with a block size of 64 bytes and a total size of 2 KB, meaning there are 32 blocks in the cache.
The addresses of P, Q, R, and S are given in hexadecimal, and we need to determine which cache block they map to.
1. Mapping of addresses to cache blocks:
The addresses are 16 bits long, and the cache block size is 64 bytes, so the block index is determined by the lower 6 bits of the address. The addresses map as follows:
- P: Address 0xA248 → Maps to cache block (P maps to a specific block in the cache).
- Q: Address 0xC28A → Maps to another cache block.
- R: Address 0xCA8A → Maps to a different block.
- S: Address 0xA262 → Maps to the same cache block as P.
2. Statement (A): Every access to S is a hit because S shares the same cache block as P and they are accessed together 10 times.
3. Statement (B): Once P is brought into the cache, it is never evicted. Since P and S map to the same cache block, once P is placed in the cache, it stays there until S is accessed.
4. Statement (D): Every access to R evicts Q from the cache because R and Q map to the same cache block (determined by the block index), and since R is accessed after Q, it replaces Q in the cache.
Thus, the correct answers are (A), (B), and (D).