Step 1: Find the length of string K.
String P has length \(l\) and it forms the diameter of the semicircular arc bent from string K, as shown in Figure (i).
A full circle with diameter \(l\) has circumference \(\pi l\). A semicircular arc of the same diameter is exactly half of that circle's boundary, so its length is \(\dfrac{\pi l}{2}\).
So the length of string K is \(\dfrac{\pi l}{2}\).
Step 2: Write the new lengths after both strings are shortened.
Each string loses the same length \(x\) when it is shortened.
The shortened string P has length \(l - x\), and Figure (ii) shows this shortened string P acting as the diameter of a full circle formed by the shortened string K.
The shortened string K has length \(\dfrac{\pi l}{2} - x\).
Step 3: Set up the circle equation.
Since the shortened string K is bent into a complete circle whose diameter is the shortened string P, the length of the shortened string K must equal the circumference of that circle.
\[ \frac{\pi l}{2} - x = \pi(l - x) \]
Step 4: Solve for the ratio \(x/l\).
Expand the right side of the equation:
\[ \frac{\pi l}{2} - x = \pi l - \pi x \]
Collect the \(x\) terms on one side and the \(l\) terms on the other:
\[ \pi x - x = \pi l - \frac{\pi l}{2} \]
\[ x(\pi - 1) = \frac{\pi l}{2} \]
Divide both sides by \(l(\pi - 1)\):
\[ \frac{x}{l} = \frac{\pi}{2(\pi - 1)} \]
Step 5: Check why the other options are wrong.
Option (A), \(\pi\), comes up if someone sets the shortened K length equal to \(\pi l\) instead of \(\pi(l-x)\), forgetting that the new circle's diameter is the shortened P, not the original P.
Option (B), \(\dfrac{\pi-1}{2\pi}\), is the reciprocal-looking flip of the correct ratio, picked up by inverting the equation at the wrong step.
Option (D), \(\dfrac{\pi}{\pi-1}\), appears if the factor of \(\dfrac{1}{2}\) from the semicircle length is dropped, effectively treating string K's original length as \(\pi l\) instead of \(\dfrac{\pi l}{2}\).
Final Answer:
The value of \(x/l\) is \(\dfrac{\pi}{2(\pi - 1)}\), which is option (C). \[ \boxed{\dfrac{x}{l} = \dfrac{\pi}{2(\pi-1)}} \]