The depletion width ratio is given by:
Wp / Wn = ND / NA
Wp / Wn = 10²² / 10²³ = 0.1
Wn = Wp / 0.1
Wn = 1.6 µm
Thus, the depletion width in the n-side is 1.6 µm.
Match the LIST-I with LIST-II
| LIST-I | LIST-II |
|---|---|
| A. Mobility of electrons (\(\mu\)) | I. \( Ne^2\tau/m \) |
| B. Drift velocity of electrons (\(v_d\)) | II. \( \mu E \) |
| C. Electrical conductivity of conduction electrons (\(\sigma\)) | III. \( \mu m/e \) |
| D. Relaxation time of electrons (\(\tau\)) | IV. \( 1/\rho ne \) |
Choose the correct answer from the options given below:
