Question:

Condensation product of caprolactam is

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Caprolactam gives Nylon-6. Hexamethylene diamine and adipic acid give Nylon-66.
Updated On: May 5, 2026
  • Nylon-6
  • Nylon-66
  • Nylon-60
  • Nylon-6,10
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The Correct Option is A

Solution and Explanation

Concept:
Caprolactam is a cyclic amide. It undergoes polymerization to form Nylon-6. Nylon-6 is a polyamide because it contains repeated amide linkages: \[ -CONH- \]

Step 1:
Identify caprolactam.
Caprolactam contains six carbon atoms in the repeating unit. That is why the polymer formed from it is called Nylon-6.

Step 2:
Polymerization of caprolactam.
Caprolactam undergoes ring-opening polymerization. The ring opens and many units join together. The product is: \[ [-NH-(CH_2)_5-CO-]_n \] This is Nylon-6.

Step 3:
Differentiate from Nylon-66.
Nylon-66 is prepared from: \[ \text{hexamethylene diamine} \] and \[ \text{adipic acid} \] It is not prepared from caprolactam.

Step 4:
Check the options.
Option (A) Nylon-6 is correct.
Option (B) Nylon-66 is incorrect.
Option (C) Nylon-60 is not the product.
Option (D) Nylon-6,10 is prepared from different monomers. Hence, the correct answer is: \[ \boxed{(A)\ \text{Nylon-6}} \]
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