Question:
Concentrated \(\mathrm{HNO_3}\) used in the laboratory is \(68\%\) by mass and its density is \(1.5\ \mathrm{g\,mL^{-1}}\). If \(x\) mL of this acid was taken into a 5 L standard flask and filled up to the mark with distilled water to prepare \(5\) L of \(0.5\ \mathrm{M}\ \mathrm{HNO_3}\) solution. What is the value of \(x\) in mL?
Concentrated \(\mathrm{HNO_3}\) used in the laboratory is \(68\%\) by mass and its density is \(1.5\ \mathrm{g\,mL^{-1}}\). If \(x\) mL of this acid was taken into a 5 L standard flask and filled up to the mark with distilled water to prepare \(5\) L of \(0.5\ \mathrm{M}\ \mathrm{HNO_3}\) solution. What is the value of \(x\) in mL?
Show Hint
Use
\[
\boxed{\text{Mass}=\frac{\text{Required mass of solute}}{\%\text{ by mass}/100}}
\]
and then
\[
\boxed{\text{Volume}=\frac{\text{Mass}}{\text{Density}}.}
\]
Updated On: Jul 15, 2026
- \(15.44\)
- \(154.4\)
- \(1544\)
- \(77.2\)
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Calculate moles required.
\[
M=\frac{n}{V}
\]
\[
n=0.5\times5=2.5\ \text{mol}
\]
Mass of pure \(\mathrm{HNO_3}\)
\[
=2.5\times63=157.5\ \text{g}
\]
Step 2: Calculate mass of concentrated acid. Since acid is \(68\%\) by mass, \[ \text{Mass of solution} =\frac{157.5}{0.68} =231.6\ \text{g} \] Volume required \[ =\frac{231.6}{1.5} =154.4\ \text{mL} \] Therefore, \[ \boxed{154.4\ \text{mL}} \] Hence, \[ \boxed{(B)} \] is the correct answer.
Step 2: Calculate mass of concentrated acid. Since acid is \(68\%\) by mass, \[ \text{Mass of solution} =\frac{157.5}{0.68} =231.6\ \text{g} \] Volume required \[ =\frac{231.6}{1.5} =154.4\ \text{mL} \] Therefore, \[ \boxed{154.4\ \text{mL}} \] Hence, \[ \boxed{(B)} \] is the correct answer.
Was this answer helpful?
0
0
Top TS EAMCET Chemistry Questions
- A, B and C are three biomolecules. The results of the tests performed on them are given below :A, B and C are respectively :
Molisch's lest Barfoed Test Biuret Test A Positive Negative Negativde B Positive Positive Negative C Negative Negative Positive - 1 mole of $H_2$ and 2 moles of $I_2$ are taken initially in a 2 litre vessel. The number of moles of $H_2$ at equilibrium is 0.2. Then the number of moles of $I_2$ and HI at equilibrium is
- The pH of a buffer containing equal molarconcentration of a weak base and its chloride ( $K_b$ for weak base = $2 \times 10^{-5}$, log 2 = 0.3) is
- Atomic radius (pm) of Al, Si, N and F respectively is
- Consider the following electrode process of a cell, $ {Cl^{-1} -> \frac{1}{2} Cl_2 + e^{-}}$ $ {[MCl + e^{-} -> M + Cl^{-} ] }$ If EMF of this cell is $-1.140\, V$ and $E^0$ value of the cell is $-0.55\,V$ at $298\,K$, the value of the equilibrium constant of the sparingly soluble salt MCl is in the order of
View More Questions
Top TS EAMCET Molality and Molarity Questions
- 100 g of a mixture of $NaOH$ and $Na_{2}SO_{4}$ is neutralized by 100 ml of 0.5M $H_{2}SO_{4}$. What is the amount of $Na_{2}SO_{4}$ present in the mixture?}
- A water sample is contaminated with compound X (molar mass \(=120g~mol^{-1}\)). Its molality is \(10^{-4}m\). What is its concentration in ppm?
Top TS EAMCET Questions
- A bag contains $5$ red balls, $3$ black balls and $4$ white balls are drawn at random. The probability that they are not of same colour is
- If $cosec\, \theta - \cot \theta = 2017$, then quadrant in which $\theta $ lies is
- If $a$ is a unit vector, then $| a \times \hat{ i }|^{2}+| a \times \hat{ j }|^{2}+| a \times \hat{ k }|^{2}=$
- $A$ straight line makes an intercept on the $Y$-axis twice as long as that on $X$-axis and is at a unit distance from the origin. Then the line is represented by the equations
- Let $S$ and $S'$ be the foci of an ellipse and B be one end of its minor axis. If $SBS'$ is an isosceles right angled triangle then the eccentricity of the ellipse is
View More Questions